\(\left|x\right|-1\dfrac{2}{3}=0\\ \Rightarrow\left|x\right|=0+\dfrac{5}{3}\\ \Rightarrow\left|x\right|=\dfrac{5}{3}\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{5}{3}\\x=-\dfrac{5}{3}\end{matrix}\right.\)
Mà `x>0`
`=> x=5/3`
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\(2\left|x\right|-3=11\\ \Rightarrow2\left|x\right|=11+3\\ \Rightarrow2\left|x\right|=14\\ \Rightarrow\left|x\right|=\dfrac{14}{2}=7\\ \Rightarrow\left[{}\begin{matrix}x=7\\x=-7\end{matrix}\right.\)
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