Lời giải:
d.
$3\sqrt{7}=\sqrt{3^2.7}=\sqrt{63}< \sqrt{64}=8$
e.
$\sqrt{17}+\sqrt{50}> \sqrt{16}+\sqrt{49}=4+7=11$
f.
$(\sqrt{50+2})^2=50+2=52$
$(\sqrt{50}+\sqrt{2})^2=50+2+2\sqrt{50.2}=52+20> 52$
$\Rightarrow (\sqrt{50+2})^2< (\sqrt{50}+\sqrt{2})^2$
$\Rightarrow \sqrt{50+2}< \sqrt{50}+\sqrt{2}$