Bài 8:
\(\left|x+2\right|+\left|\dfrac{4}{5}-2y\right|=0\\ \Leftrightarrow\left\{{}\begin{matrix}x+2=0\\\dfrac{4}{5}-2y=0\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x=-2\\\dfrac{4}{5}=2y\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x=-2\\y=\dfrac{4}{5}:2=\dfrac{2}{5}\end{matrix}\right.\)
