Question

Answer 1

\(B39:\\ a,MSC:x^2y\\ Ta.có:\dfrac{1}{x^2y}=\dfrac{1}{x^2y};\dfrac{3}{xy}=\dfrac{3x}{3x^2y}\\ b,MSC:\left(x+y\right)^2\\ Ta.có:\dfrac{x}{x^2+2xy+y^2}=\dfrac{x}{\left(x+y\right)^2}\\ \dfrac{2x}{x^2+xy}=\dfrac{2x}{x\left(x+y\right)}=\dfrac{2}{x+y}=\dfrac{2\left(x+y\right)}{\left(x+y\right)^2}\)

Answer 2

mn giúp e vs ạ , e đg gấp , e cảm ơn 

 

Answer 3

\(B41:\\ x^2+3x+2=\left(x+1\right)\left(x+2\right)\\ x^2+4x+3=\left(x+1\right)\left(x+3\right)\\ MTC:\left(x+1\right)\left(x+2\right)\left(x+3\right)\\ \)