`@` `\text {Ans}`
`\downarrow`
`a)`
`M = A + B`
`=`\(x^3-x^2-2x+1-x^3+x^2\)
`= (x^3 - x^3) + (-x^2 + x^2) -2x + 1`
`= -2x + 1`
Vậy, `M=-2x+1`
`b)`
Thay `x=1` vào M
`M = -2*1 + 1 = -2 + 1 = -1`
Vậy, `M = -1`
`c)`
`M = 0`
`=> -2x + 1 = 0`
`=> -2x = 0 - 1`
`=> -2x = -1`
`=> 2x = 1`
`=> x = 1/2`
Vậy, `x = 1/2.`


