\(9.\\a) n_{CuCl_2}=\dfrac{13,5}{135}=0,1\left(mol\right)\\ CuCl_2+2NaOH\rightarrow2NaCl+Cu\left(OH\right)_2\\n_{CuCl_2}=n_{Cu\left(OH\right)_2}=0,1mol\\ m_{Cu\left(OH\right)_2}=0,1.98=9,8\left(g\right)\\ b) Cu\left(OH\right)_2\xrightarrow[]{t^0}CuO+H_2O\\ n_{CuO}=n_{Cu\left(OH\right)_2}=0,1mol\\ m_{CuO}=0,1.80=8\left(g\right)\)
\(11.\\ a)m_{H_2O}=19,7-16,1=3,6\left(g\right)\\ n_{H_2O}=\dfrac{3,6}{18}=0,2\left(mol\right)\\ n_{Cu\left(OH\right)_2}=a;n_{H_2}=b\\ Cu\left(OH\right)_2\xrightarrow[t^0]{}CuO+H_2O\\ Zn\left(OH\right)_2\xrightarrow[t^0]{}ZnO+H_2O\\ b)\left\{{}\begin{matrix}98a+99b=19,7\\a+b=0,2\end{matrix}\right.\\ \Rightarrow a=b=0,1mol\\ m_{Cu\left(OH\right)_2}=0,1.98=9,8g\\ m_{Zn\left(OH\right)_2}=19,7-9,8=9,9g\)
12
a
\(2Fe\left(OH\right)_3\underrightarrow{t^o}Fe_2O_3+3H_2O\)
0,2--------->0,1
\(n_{Fe\left(OH\right)_3}=\dfrac{21,4}{107}=0,2\left(mol\right)\)
b
\(m_B=m_{Fe_2O_3}=0,2.160=16\left(g\right)\)
13
\(Cu\left(OH\right)_2\underrightarrow{t^o}CuO+H_2O\)
x----------->x
\(2Fe\left(OH\right)_3\underrightarrow{t^o}Fe_2O_3+3H_2O\)
y------------>0,5y
Có hệ: \(\left\{{}\begin{matrix}98x+107y=15,6\\80x+160.0,5y=12\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=0,05\\y=0,1\end{matrix}\right.\)
\(\%m_{CuO}=\dfrac{80.0,05.100\%}{12}=33,33\%\\ \%m_{Fe_2O_3}=\dfrac{160.0,5.0,1.100\%}{12}=66,67\%\)
\(13.\\ a)Cu\left(OH\right)_2\xrightarrow[]{t^0}CuO+H_2O\\ 2Fe\left(OH\right)_3\xrightarrow[]{t^0}Fe_2O_3+3H_2O\\ b)m_{H_2O}=15,6-12=3,6g\\ n_{Cu\left(OH\right)_2}=a;n_{Fe\left(OH\right)_3}=b\\ \left\{{}\begin{matrix}98a+107.2b=15,6\\\left(a+3b\right).18=3,6\end{matrix}\right.\\ \Rightarrow a=b=0,05\\ \%_{CuO}=\dfrac{0,05.80}{12}\cdot100=33\%\\ \%_{Fe_2O_3}=100-33=67\%\)
\(10.\\ a)Cu\left(OH\right)_2\xrightarrow[]{t^0}CuO+H_2O\\ b)n_{Cu\left(OH\right)_2}=\dfrac{9,8}{98}=0,1\left(mol\right)\\ n_{CuO}=n_{Cu\left(OH\right)_2}=0,1mol\\ m_{CuO}=0,1.80=8g\)
\(12.\\ a)2Fe\left(OH\right)_3\xrightarrow[]{t^0}Fe_2O_3+3H_2O\\ b)n_{Fe\left(OH\right)_3}=\dfrac{21,4}{107}=0,2mol\\ m_{Fe_2O_3}=0,2:2.160=16\left(g\right)\)
