Thay `A^2 . B^3 . C`
Ta có : `A=3x^2y ; B=-2xy^2;C=1/10x^3y^4`
Vậy `A^2.B^3.C`
`= (3x^2y)^2 . (-2xy^2)^3 . ( 1/10 x^3 y^4)`
`= 9x^4y^2 . ( -8 x^3y^5) . 1/10 x^3y^4`
\(=\left[9.\left(-8\right).\dfrac{1}{10}\right].\left(x^4.x^3.x^3\right).\left(y^2.y^5.y^4\right)\\ =-\dfrac{36}{5}.x^{10}.y^{11}\)


