Chọn \(m_{rắn\left(ban.đầu\right)}=100\left(g\right)\) \(\Rightarrow m_{rắn\left(sau\right)}=50\left(g\right)\)
PTHH: \(CaCO_3\xrightarrow[]{t^o}CaO+CO_2\uparrow\)
\(MgCO_3\xrightarrow[]{t^o}MgO+CO_2\uparrow\)
Đặt \(\left\{{}\begin{matrix}n_{CaCO_3}=a\left(mol\right)=n_{CaO}\\n_{MgCO_3}=b\left(mol\right)=n_{MgO}\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}100a+84b=100\\56a+40b=50\end{matrix}\right.\)
\(\Rightarrow.....\)