Question

Answer 1

\(a)\dfrac{-5}{8}+\dfrac{1}{8}=\dfrac{-5+1}{8}=-\dfrac{4}{8}=-\dfrac{1}{2}\\ b)\dfrac{11}{7}-\dfrac{-5}{8}=\dfrac{11\times3}{7\times3}-\dfrac{-5}{21}=\dfrac{33}{21}-\dfrac{-5}{21}=\dfrac{33-\left(-5\right)}{21}=\dfrac{38}{21}=\\ c)\dfrac{-3}{4}+\dfrac{-1}{4}+\dfrac{2}{7}+\dfrac{5}{7}+\dfrac{3}{5}\\ =\left(\dfrac{-3}{4}+\dfrac{-1}{4}\right)+\left(\dfrac{2}{7}+\dfrac{5}{7}\right)+\dfrac{3}{5}\\ =\left(\dfrac{-3+\left(-1\right)}{4}\right)+\left(\dfrac{2+5}{7}\right)+\dfrac{3}{5}\\ =\dfrac{-4}{4}+\dfrac{7}{7}+\dfrac{3}{5}\\ =-1+1+\dfrac{3}{5}\\ =\dfrac{3}{5}\)