Câu `1`
`->C`
Câu `2`
`->C`
`x-1=2x-5`
`<=> x-2x=-5+1`
`<=> -x=-4`
`<=>x=4`
Câu `3`
`->B`
`(3x-7)(x-1)=0`
\(\Leftrightarrow\left[{}\begin{matrix}3x-7=0\\x-1=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}3x=7\\x=1\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{7}{3}\\x=1\end{matrix}\right.\)


