Question

Answer 1

`@` `\text {dnammv}`

`a,`

`x \div 9 = -2 \div 1,2`

`x/9=-2/(1,2)`

`-> 1,2x=9*-2`

`-> 1,2x=-18`

`-> x=-18 \div 1,2`

`-> x=-15`

Vậy, `x=-15`

`b,`

\(\dfrac{2x-1}{-32}=\dfrac{-2}{2x-1}\)

`-> (2x-1)(2x-1)=(-32)*(-2)`

`-> (2x-1)^2=64`

`-> (2x-1)^2=(+-8)^2`

`-> `\(\left[{}\begin{matrix}2x-1=8\\2x-1=-8\end{matrix}\right.\)

`->`\(\left[{}\begin{matrix}2x=8+1\\2x=-8+1\end{matrix}\right.\)

`->`\(\left[{}\begin{matrix}2x=9\\2x=-7\end{matrix}\right.\)

`->`\(\left[{}\begin{matrix}x=\dfrac{9}{2}\\x=-\dfrac{7}{2}\end{matrix}\right.\)

Vậy, `x={9/2 ; -7/2}`