Question

Answer 1

nZn = 19.5/65 = 0.3 (mol) 

Zn + H2SO4 => ZnSO4 + H2 

0.3..........................0.3.......0.3

VH2 = 0.3*22.4 = 6.72 (l) 

mZnSO4 = 0.3*161 = 48.3 (g) 

Answer 2

1) nZn=0,3(mol)

PTHH: Zn + H2SO4 -> ZnSO4 + H2

0,3________0,3____0,3______0,3(mol)

a) V(H2,đktc)=0,3.22,4=6,72(l)

b) mZnSO4=161. 0,3= 48,3(g)