\(A=\dfrac{4\left(x^2+9\right)-\left(4x^2+12x+9\right)}{x^2+9}=4-\dfrac{\left(2x+3\right)^2}{x^2+9}\le4\)
\(A_{max}=4\) khi \(x=-\dfrac{3}{2}\)
\(A=\dfrac{-\left(x^2+9\right)+x^2-12x+36}{x^2+9}=-1+\dfrac{\left(x-6\right)^2}{x^2+9}\ge-1\)
\(A_{min}=-1\) khi \(x=6\)


