1)\(3\left(x+2\right)>2x-1\)
\(\Leftrightarrow3x+2>2x-1\)
\(\Leftrightarrow3x-2x>-1-2\)
\(\Leftrightarrow x>-3\)
Vậy bất phương trình có nghiệm là: \(S=\left\{xIx>-3\right\}\)
2)\(\dfrac{x+1}{2}-\dfrac{3x-5}{3}\ge\dfrac{x}{4}+3\)
\(\Leftrightarrow\dfrac{\left(x+1\right)6}{2.6}-\dfrac{\left(3x-5\right).4}{3.4}\ge\dfrac{x.3}{4.3}+\dfrac{3.12}{1.12}\)
\(\Rightarrow6x+6-12x+20\ge3x+36\)
\(\Leftrightarrow6x-12x-3x\ge36-6-20\)
\(\Leftrightarrow-9x\ge10\)
\(\Leftrightarrow-9x\cdot\dfrac{-1}{9}\le10.\dfrac{-1}{9}\)
⇔\(x\le-\dfrac{10}{9}\)
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