a/\(\dfrac{17}{18}=\dfrac{9}{18}+\dfrac{6}{18}+\dfrac{2}{18}=\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{9}\)
b/\(\dfrac{9}{12}=\dfrac{3}{4}=\dfrac{1}{4}+\dfrac{1}{4}+\dfrac{1}{4}\)
\(a,\dfrac{17}{18}=\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{9}\\ b,\dfrac{9}{12}=\dfrac{1}{6}+\dfrac{1}{4}+\dfrac{1}{3}\)
