\(\widehat{A}+\widehat{B}+\widehat{C}=180^o\\ \widehat{C}=180^o-\widehat{A}+\widehat{B}\Leftrightarrow180^o-60^o+50^o=70^o\)
vì \(\Delta ABC\sim\Delta MNP\Leftrightarrow\Delta ABC=\Delta MNP\)
nên \(\widehat{A}=\widehat{M}=60^o\\ \widehat{B}=\widehat{N}=50^o\\ \widehat{C}=\widehat{B=70^o}\)
đáp án C