\(\left(-\dfrac{1}{8}x^2\right).12x^5=-\dfrac{3}{2}x^7\)
\(\dfrac{2}{3}x^2.\left(-3x\right)^2=6x^4\)
\(-x^4.\dfrac{x}{6}.\left(-\dfrac{3}{4}x^2\right)=\dfrac{1}{8}x^7\)
\(\left(1\dfrac{1}{2}x^3\right)^3.4x^2=\left(\dfrac{3}{2}x^3\right)^3.4x^2=\dfrac{27}{2}x^{11}\)
