`(2a+1)^2-16(a+1)^2`
`=(2a+1)^2-(4a+4)^2`
`=(2a+1-4a-4)(2a+1+4a+4)=(-2a-3)(6a+5)`
`=>` Chỗ cần điền là: `6`
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`(x+y)^3-3xy(x+y)`
`=(x+y)[(x+y)^2-3xy]`
`=(x+y)(x^2+2xy+y^2-3xy)`
`=(x+y)(x^2-xy+y^2)=x^3+y^3`
`=>a=1;b=1`
`=>a-b=1-1=0`



