Câu 2:
\(\left\{{}\begin{matrix}x_1+x_2=\dfrac{7}{2}\\x_1x_2=\dfrac{-6}{2}=-3\end{matrix}\right.\)
\(A=4x_1x_2\left(x_1^2+x_2^2\right)\)
\(=4\cdot\left(-3\right)\cdot\left[\left(x_1+x_2\right)^2-2x_1x_2\right]\)
\(=-12\cdot\left[\left(\dfrac{7}{2}\right)^2-2\cdot\left(-3\right)\right]=-12\left[\dfrac{49}{4}+6\right]\)
\(=-49\cdot3-12\cdot6=-147-72=-219\)