Nếu thế thì mình làm 2 câu bạn khoanh nha .
c)
\(\left(x-1\right)^3=\dfrac{1}{8}\)
\(\left(x-1\right)^3=\left(\dfrac{1}{2}\right)^3\)
\(x-1=\dfrac{1}{2}\)
\(x=\dfrac{1}{2}+1\)
\(x=\dfrac{3}{2}\)
d)
\(\left(\dfrac{1}{3}-\dfrac{3}{2}x\right)^2=\dfrac{9}{4}\)
\(\left(\dfrac{1}{3}-\dfrac{3}{2}x\right)^2=\left(\dfrac{3}{2}\right)^2\)
\(\Rightarrow\dfrac{1}{3}-\dfrac{3}{2}x=\dfrac{3}{2}\) hoặc \(\dfrac{1}{3}-\dfrac{3}{2}x=-\dfrac{3}{2}\)
\(\Rightarrow\left[{}\begin{matrix}\dfrac{1}{3}-\dfrac{3}{2}x=\dfrac{3}{2}\\\dfrac{1}{3}-\dfrac{3}{2}x=-\dfrac{3}{2}\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}\dfrac{3}{2}x=\dfrac{1}{3}-\dfrac{3}{2}\\\dfrac{3}{2}x=\dfrac{1}{3}-\left(-\dfrac{3}{2}\right)\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}\dfrac{3}{2}x=-\dfrac{7}{6}\\\dfrac{3}{2}x=\dfrac{11}{6}\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=-\dfrac{7}{6}:\dfrac{3}{2}\\x=\dfrac{11}{6}:\dfrac{3}{2}\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=-\dfrac{7}{9}\\x=\dfrac{11}{9}\end{matrix}\right.\)
