Question

Answer 1

a)

\(x^2-4x-y^2+4\\ =\left(x^2-4x+4\right)-y^2\\ =\left(x-2\right)^2-y^2\\ =\left(x-2-y\right)\left(x-2+y\right)\)

b)

\(x^2+5x-2x-10\\ =x\left(x+5\right)-2\left(x+5\right)\\ =\left(x+5\right)\left(x-2\right)\)

Answer 2

\(a,x^2-4x-y^2+4\\ =\left(x^2-4x+4\right)-y^2\\ =\left(x-2\right)^2-y^2\\ =\left(x-2-y\right)\left(x-2+y\right)\\ b,x^2+3x-10\\ =x^2+5x-2x-10\\ =x\left(x+5\right)-2\left(x+5\right)\\ =\left(x-2\right)\left(x+5\right)\)

Answer 3

`x^2 - 4x-y^2 + 4`

`=(x^2 - 4x +4)-y^2`

`=(x-2)^2 -y^2`

`=(x-2+y).(x-2+y)`

________________

`x^2 +3x - 10`

`=x^2 + 5x -2x - 10`

`=(x^2 + 5x)-(2x+10)`

`=x.(x+5) - 2.(x+5)`

`=(x+5).(x-2)`