\(\dfrac{x^2-x}{2\left(x-1\right)}=\dfrac{x\left(x-1\right)}{2\left(x-1\right)}=\dfrac{x}{2}\\ =>B\)
\(\dfrac{x^2-x}{2\times\left(x-1\right)}=\dfrac{x\times\left(x-1\right)}{2\times\left(x-1\right)}=\dfrac{x}{2}\)
\(\Rightarrow ChonB\)
\(\dfrac{x^2-x}{2\left(x-1\right)}=\dfrac{x\left(x-1\right)}{2\left(x-1\right)}=\dfrac{x}{2}\)
=> Chọn B


