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Rip_kira
Rip_kira
23 tháng 12 2022 lúc 18:11

giúp mình bài 1 với ạ

 

『Kuroba ム Tsuki Ryoo...
23 tháng 12 2022 lúc 18:35

\(\dfrac{3}{5}+\left(-\dfrac{3}{7}\right)+\left(-\dfrac{3}{5}\right)=\left(\dfrac{3}{5}+-\dfrac{3}{5}\right)+\dfrac{3}{7}=0+\dfrac{3}{7}=\dfrac{3}{7}.\)

\(b,\left(-\dfrac{7}{4}.\dfrac{3}{8}+-\dfrac{7}{4}.\dfrac{5}{8}\right)+\dfrac{7}{15}\div-\dfrac{14}{5}\)

\(=\left(-\dfrac{7}{4}.\left(\dfrac{3}{8}+\dfrac{5}{8}\right)\right)+-\dfrac{5}{2}\)

\(=\left(-\dfrac{7}{4}.1\right)+-\dfrac{5}{2}\)

\(=-\dfrac{7}{4}+-\dfrac{5}{2}=-\dfrac{17}{4}\)

\(c,\left(\sqrt{0,25}-1.2\right)\div1\dfrac{1}{20}-\left(-\dfrac{5}{2}\right)^2-\left|-\dfrac{1}{12}\right|\)

\(=\left(0,5-1,2\right)\div1\dfrac{1}{20}-\dfrac{25}{4}-\dfrac{1}{12}\)

\(=-0,7\div\dfrac{21}{20}-\dfrac{25}{4}-\dfrac{1}{12}\)

\(=-\dfrac{2}{3}-\dfrac{25}{4}-\dfrac{1}{12}=-7\)