Question

Answer 1

\(8-\left|1-3x\right|=3\\ \left|1-3x\right|=8-3\\ \left|1-3x\right|=5\\ =>\left[{}\begin{matrix}1-3x=5\\1-3x=-5\end{matrix}\right.\left[{}\begin{matrix}3x=1-5\\3x=1-\left(-5\right)\end{matrix}\right.\left[{}\begin{matrix}3x=-4\\3x=6\end{matrix}\right.\left[{}\begin{matrix}x=-4:3\\x=6:3\end{matrix}\right.\left[{}\begin{matrix}x=-\dfrac{4}{3}\\x=2\end{matrix}\right.\)

Answer 2

8- l1-3xl=3

    l1-3xl=5

=>1-3x∈{-5;5}

Nếu 1-3x=-5

           3x=6

             x=2

Nếu 1-3x=5

           3x=-4

             x=\(\dfrac{-4}{3}\) 

Vậy x ∈{2;\(\dfrac{-4}{3}\)}

Answer 3

\(8-\left|1-3x\right|=3\)

\(\left|1-3x\right|=8-3\)

\(|1-3x|=5\)

\(\Rightarrow\left[{}\begin{matrix}1-3x=5\\1-3x=-5\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}3x=1-5\\3x=1-\left(-5\right)\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}3x=-4\\3x=6\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=-4:3\\x=6:3\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{-4}{3}\\x=2\end{matrix}\right.\)

Vậy \(x\in\left\{\dfrac{-4}{3};2\right\}\)

Answer 4

\(3,8-\left|1-3x\right|=3\)

\(\Rightarrow\left|1-3x\right|=5\)

\(\Rightarrow\left[{}\begin{matrix}1-3x=5\\1-3x=-5\end{matrix}\right.\)              \(\Rightarrow\left[{}\begin{matrix}3x=-4\\3x=6\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{-4}{3}\\x=2\end{matrix}\right.\)               Vậy \(x\in\left\{\dfrac{-4}{3};2\right\}\)

Answer 5