Question

Answer 1

a,PTHH:\(CaC_2+2H_2O\rightarrow C_2H_2+Ca\left(OH\right)_2\)

 

b,Theo định luật bảo toàn khối lượng ,ta có:

\(m_{CaC_2}+m_{H_2O}=m_{C_2H_2}+m_{Ca\left(OH\right)_2}\)

\(\Rightarrow m_{H_2O}=m_{C_2H_2}+m_{Ca\left(OH\right)_2}-m_{CaC_2}\)

\(\Rightarrow m_{H_2O}=13+37-41=9\left(gam\right)\)

\(V_{H_2O}=\dfrac{m}{D}=\dfrac{9}{1}=9\left(ml\right)\)