\(\left(x-\dfrac{1}{2}\right)^2=2^3:\sqrt{4}\)
\(\left(x-\dfrac{1}{2}\right)^2=8:2\)
\(\left(x-\dfrac{1}{2}\right)^2=4\\ =>\left[{}\begin{matrix}x-\dfrac{1}{2}=2\\x-\dfrac{1}{2}=-2\end{matrix}\right.\\ \left[{}\begin{matrix}x=2+\dfrac{1}{2}\\x=-2+\dfrac{1}{2}\end{matrix}\right.\\ \left[{}\begin{matrix}x=\dfrac{5}{2}\\x=-\dfrac{3}{2}\end{matrix}\right.\)
\(\left(x-\dfrac{1}{2}\right)^2=2^3:\sqrt{4}\)
\(\Leftrightarrow x^2-2\times\dfrac{1}{2}x+\dfrac{1}{4}=8:2\)
\(\Leftrightarrow x^2-x+\dfrac{1}{4}=4\)
\(\Leftrightarrow x\left(x-1\right)=\dfrac{15}{4}\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{15}{4}\\x-1=\dfrac{15}{4}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{15}{4}\\x=\dfrac{19}{4}\end{matrix}\right.\)
..............
(x-1/2)^2=2^3:2
(x-1/2)^2=2^2
x-1/2=2 hoặc x-1/2=-2
TH1:x-1/2=2
x=5/2
TH2:x-1/2=-2
x=-3=2
Vậy x =5/2 hoặc x=-3/2
