a. \(\left\{{}\begin{matrix}I=\dfrac{P}{U}=\dfrac{1500}{220}=\dfrac{75}{11}A\\R=\dfrac{U^2}{P}=\dfrac{220^2}{1500}=\dfrac{484}{15}\Omega\end{matrix}\right.\)
b. Ta có: \(A=Pt=1500\cdot\dfrac{20}{60}\cdot30=15000\)Wh = 15kWh
\(\Rightarrow T=A\cdot1500=15\cdot1500=22500\left(dong\right)\)


