\(A=2+2^2+2^3+...+2^{20}\)
\(=\left(2+2^2+2^3+2^4\right)+\left(2^5+2^6+2^7+2^8\right)+...+\left(2^{17}+2^{18}+2^{19}+2^{20}\right)\)
\(=2\left(1+2+2^2+2^3\right)+2^5\left(1++2+2^2+2^3\right)+...+2^{17}\left(1+2+2^2+2^3\right)\)
\(=2.15+2^5.15+...+2^{17}.15\)
\(=5.\left(2.3+2^5.3+...+2^{17}.3\right)⋮5\)
Vậy \(A⋮5\)
