a) \(n_{ZnO}=\dfrac{40,5}{81}=0,5\left(mol\right)\)
PTHH: ZnO + H2SO4 (loãng) ---> ZnSO4 + H2O
0,5--->0,5------------------->0,5
`=>` \(m_{ddH_2SO_4}=\dfrac{0,5.98}{20\%}=245\left(g\right)\)
`=>` \(m_{ddspư}=245+40,5=285,5\left(g\right)\)
`=>` \(C\%_{ZnSO_4}=\dfrac{0,5.161}{285,5}.100\%=28,2\%\)
