\(e.\left(\dfrac{2x-1}{3}\right)^2=\dfrac{1}{4}\\ \dfrac{2x-1}{3}=\dfrac{1}{2}\\\dfrac{2x}{3}-\dfrac{1}{3}=\dfrac{1}{2}\\ \dfrac{2x}{3}=\dfrac{1}{2}+\dfrac{1}{3}\\ \dfrac{2x}{3}= \dfrac{5}{6}\\ 2x=\dfrac{5}{6}\times3\\ 2x=\dfrac{5}{2}\\ x=\dfrac{5}{2}:2\\ x=5\)