Question

  

Answer 1

a) Theo ĐLBTKL: \(m_{O_2}=m_{CO_2}+m_{H_2O}-m_A=26,4+5,4-7,8=24\left(g\right)\)

`=>` \(n_{O_2}=\dfrac{24}{32}=0,75\left(mol\right)\Rightarrow V_{O_2}=0,75.22,4=16,8\left(l\right)\)

b) Theo ĐLBTNT: \(\left\{{}\begin{matrix}n_C=n_{CO_2}=\dfrac{26,4}{44}=0,6\left(mol\right)\\n_H=2n_{H_2O}=\dfrac{2.5,4}{18}=0,6\left(mol\right)\end{matrix}\right.\)

`=>` \(\left\{{}\begin{matrix}\%m_C=\dfrac{0,6.12}{7,8}.100\%=92,31\%\\\%m_H=\dfrac{0,6}{7,8}.100\%=7,69\%\end{matrix}\right.\)

c) Ta có: \(m_C+m_H=0,6.12+0,6=7,8\left(g\right)=m_A\)

`=> A` không chứa `O`