Question

Answer 1

\(5,4.\left(x-2\right)^2=6.10+2^2\\ =>4.\left(x-2\right)^2=60+4\\ =>4\left(x-2\right)^2=64\\ =>\left(x-2\right)^2=64:4\\ =>\left(x-2\right)^2=16\\ =>\left[{}\begin{matrix}\left(x-2\right)^2=4^2\\\left(x-2\right)^2=\left(-4\right)^2\end{matrix}\right.=>\left[{}\begin{matrix}x-2=4\\x-2=-4\end{matrix}\right.=>\left[{}\begin{matrix}x=6\\x=-2\end{matrix}\right.\)

Answer 2

4.(x-2)²=6.10+2²

<=>4.(x-2)²=64

<=>(x-2)²=16

<=>(x-2)²=4²

<=>\(\left[{}\begin{matrix}x-2=4\\x-2=-4\end{matrix}\right.>\left[{}\begin{matrix}x=6\\x=-2\end{matrix}\right.\)

<=>x∈{6;-2}