\(3,\dfrac{2}{5}x+\dfrac{3}{5}x-\dfrac{2}{3}=\dfrac{1}{2}\\ =>\left(\dfrac{2}{5}+\dfrac{3}{5}\right)x=\dfrac{1}{2}+\dfrac{2}{3}\\ =>\dfrac{5}{5}x=\dfrac{1\times3+2\times2}{6}\\ =>x=\dfrac{7}{6}\)
\(< =>x\left(\dfrac{2}{5}+\dfrac{3}{5}\right)=\dfrac{1}{2}+\dfrac{2}{3}< =>1x=\dfrac{7}{6}< =>x=\dfrac{7}{6}\)
\(\dfrac{2}{5}x+\dfrac{3}{5}x-\dfrac{2}{3}=\dfrac{1}{2}\)
\(=1x\) \(=\dfrac{1}{2}+\dfrac{2}{3}\)
\(x\) \(=\dfrac{7}{6}\)
