Question

Answer 1

a) \(x-\dfrac{4}{15}=\dfrac{1}{12}\)

\(x=\dfrac{1}{12}+\dfrac{4}{15}\)

\(x=\dfrac{7}{20}\)

b) \(x\times2\dfrac{2}{3}=3\dfrac{4}{8}+6\dfrac{5}{12}\)

\(x\times\dfrac{8}{3}=\dfrac{7}{2}+\dfrac{77}{12}\)

\(x\times\dfrac{8}{3}=\dfrac{119}{12}\)

\(x=\dfrac{119}{12}:\dfrac{8}{3}=\dfrac{119}{12}\times\dfrac{3}{8}\)

\(x=\dfrac{119}{32}\)

Answer 2

a)

x - \(\dfrac{4}{15}\)=\(\dfrac{1}{12}\)

x        =\(\dfrac{1}{12}\)+\(\dfrac{4}{15}\)

x        =\(\dfrac{7}{20}\)

b)

\(x\)x2\(\dfrac{2}{3}\)=3\(\dfrac{4}{8}\)+6\(\dfrac{5}{12}\)

\(x\)x\(\dfrac{8}{3}\)=\(\dfrac{119}{12}\)

\(x\)     =\(\dfrac{119}{12}\):\(\dfrac{8}{3}\)

\(x\)     = \(\dfrac{119}{32}\)

Answer 3

\(x-\dfrac{4}{15}=\dfrac{1}{12}\)

\(x=\dfrac{1}{12}+\dfrac{4}{15}\)

\(x=\dfrac{63}{180}=\dfrac{7}{20}\)