a.\(A=\left(2-\dfrac{5}{2}+1\dfrac{1}{3}\right)-\left(5,3-\dfrac{1}{5}\right)-\left(\dfrac{4}{6}-\dfrac{5}{3}\right)\)
\(A=\left(2-\dfrac{5}{2}+\dfrac{4}{3}\right)-\left(\dfrac{53}{10}-\dfrac{1}{5}\right)-\left(\dfrac{4}{6}-\dfrac{5}{3}\right)\)
\(A=\dfrac{5}{6}-\dfrac{51}{10}+1\)
\(A=-\dfrac{49}{15}\)
b.\(B=\left(\dfrac{11}{3}+\dfrac{5}{6}-\dfrac{1}{2}\right)+\left(\dfrac{4}{8}-\dfrac{1}{2}\right).\left(\dfrac{1}{3}-\dfrac{1}{2}\right)\)
\(B=4+0.\left(\dfrac{1}{3}-\dfrac{1}{2}\right)\)
\(B=4+0\)
`B=4`
