Question

Answer 1

`(2/3x-3/2y)(2/3x+3/2y)`

`= (2/3x)^2 - (3/2y)^2`

`= 4/9x^2 - 9/4 y^2`

Answer 2

câu 9 ạ

Answer 3

\(\left(\dfrac{2}{3}x-\dfrac{3}{2}y\right)\left(\dfrac{2}{3}x+\dfrac{3}{2}y\right)\)

\(=\left(\dfrac{2}{3}x\right)^2-\left(\dfrac{3}{2}y\right)^2=\dfrac{4x^2}{9}-\dfrac{9y^2}{4}\)

Answer 4

(2/3x - 3/2y) (2/3x + 3/2y)

=> 2/3x² + 3/2y²