Question

Answer 1

\(a.\dfrac{-3}{5}+\dfrac{7}{5}=\dfrac{4}{5}\)

\(b.\dfrac{5}{7}+\dfrac{-8}{7}=\dfrac{-3}{7}\)

\(c.\dfrac{7}{4}+\dfrac{11}{4}=\dfrac{18}{4}=\dfrac{9}{2}\)

\(d.\dfrac{8}{-9}+\dfrac{7}{-9}=\dfrac{-15}{9}=\dfrac{-5}{3}\)

\(e.\dfrac{14}{6}+\dfrac{8}{-3}=\dfrac{7}{3}+\dfrac{-8}{3}=\dfrac{-1}{3}\)

\(f.\dfrac{7}{-3}-\dfrac{-4}{3}=\dfrac{-7}{3}-\dfrac{-4}{3}=\dfrac{-3}{3}=-1\)

\(g.\dfrac{3}{5}-\dfrac{-9}{5}=\dfrac{12}{5}\)

\(h.\dfrac{9}{11}-\dfrac{7}{-11}=\dfrac{9}{11}-\dfrac{-7}{11}=\dfrac{16}{11}\)

\(i.\dfrac{9}{-8}-\dfrac{11}{8}=\dfrac{-9}{8}-\dfrac{11}{8}=\dfrac{-20}{8}=\dfrac{-5}{2}\)