a) Gọi \(\left\{{}\begin{matrix}n_{MgO}=x\left(mol\right)\\n_{CuO}=y\left(mol\right)\end{matrix}\right.\) `=> 40x + 80y = 22 (1)`
\(n_{HCl}=0,7.1=0,7\left(mol\right)\)
PTHH: \(MgO+2HCl\rightarrow MgCl_2+H_2O\)
x------->2x-------->x
\(CuO+2HCl\rightarrow CuCl_2+H_2O\)
y---->2y---------->y
`=> 2x + 2y = 0,7 (2)`
Từ `(1), (2) =>` \(\left\{{}\begin{matrix}x=0,15\\y=0,2\end{matrix}\right.\)
`=>` \(\left\{{}\begin{matrix}\%n_{MgO}=\dfrac{0,15}{0,15+0,2}.100\%=42,86\%\\\%n_{CuO}=100\%-42,86\%=57,14\%\end{matrix}\right.\)
b) \(\left\{{}\begin{matrix}C_{M\left(MgCl_2\right)}=\dfrac{0,15}{0,7}=\dfrac{3}{14}M\\C_{M\left(CuCl_2\right)}=\dfrac{0,2}{0,7}=\dfrac{2}{7}M\end{matrix}\right.\)
