Question

Answer 1

Ta có:

\(\dfrac{-12}{11}=\dfrac{-12.140}{11.140}=\dfrac{-1680}{1540}\)

\(\dfrac{-8}{-7}=\dfrac{8}{7}=\dfrac{8.220}{7.220}=\dfrac{1760}{1540}\)

\(\dfrac{-11}{4}=\dfrac{-11.385}{4.385}=\dfrac{-4235}{1540}\)

\(\dfrac{0}{14}=0\)

\(1\dfrac{2}{7}=\dfrac{9}{7}=\dfrac{9.220}{7.220}=\dfrac{1980}{1540}\)

\(1,6=\dfrac{16}{10}=\dfrac{8}{5}=\dfrac{8.308}{5.308}=\dfrac{2464}{1540}\)

Vì \(-4235< -1680< 0< 1760< 1980< 2464\)

\(\Rightarrow\dfrac{-4235}{1540}< \dfrac{-1680}{1540}< \dfrac{0}{1540}< \dfrac{1760}{1540}< \dfrac{1980}{1540}< \dfrac{2464}{1540}\)

\(\Rightarrow\dfrac{-11}{4}< \dfrac{-12}{11}< 0< \dfrac{-8}{-7}< 1\dfrac{2}{7}< 1,6\)

\(\Rightarrow\dfrac{-11}{4}< \dfrac{-12}{11}< \dfrac{0}{14}< \dfrac{-8}{-7}< 1\dfrac{2}{7}< 1,6\)

Vậy: \(1,6;1\dfrac{2}{7};\dfrac{-8}{-7};\dfrac{0}{14};\dfrac{-12}{11};\dfrac{-11}{4}.\)