Question

Answer 1

1/

$2Cu + O_2 \xrightarrow{t^o} 2CuO$
$CuO + 2HCl \to CuCl_2 + H_2O$
$CuCl_2 + 2KOH \to Cu(OH)_2 + 2KCl$
$Cu(OH)_2 \xrightarrow{t^o} CuO + H_2O$
$CuO + H_2 \xrightarrow{t^o} Cu + H_2O$
2/

$2Al + 3H_2SO_4 \to Al_2(SO_4)_3 + 3H_2$
$Al_2(SO_4)_3 + 6KOH \to 2Al(OH)_3 + 3K_2SO_4$
$Al(OH)_3 + NaOH \to NaAlO_2 + 2H_2O$
$4Al + 3O_2 \xrightarrow{t^o} 2Al_2O_3$
$2Al(OH)_3 \xrightarrow{t^o} Al_2O_3 + 3H_2O$
$Al_2O_3 + 2NaOH \to 2NaAlO_2 + H_2O$

Answer 2

2Cu+O2-to>2CuO

CuO+2HCl->CuCl2+H2O

CuCl2+2NaOH->Cu(OH)2+2NaCl

Cu(OH)2-to>CuO+H2O

CuO+H2-to>Cu+H2O

2.

Al+H2SO4->Al2(SO4)3+H2

Al2(SO4)3+6NaOH ->2Al(OH)3+3Na2SO4

Al(OH)3+NaOH->NaAlO2+2H2O

4Al+3O2-to>2Al2O3

2Al2(SO4)3-to->2Al2O3+3O2+6SO2

2Al(OH)3-to>Al2O3+3H2O

Al2O3+NaOH->NaAlO2+H2O