Question

Answer 1

`a)x-2/5=0,24`

`=>x-2/5=6/25`

`=>x=6/25+2/5`

`=>x=16/25`

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`b)2^[x+3].4^2=128`

`=>2^[x+3].(2^2)^2=128`

`=>2^[x+3].2^4=128`

`=>2^[x+3+4]=128`

`=>2^[x+7]=128`

`=>2^[x+7]=2^7`

`=>x+7=7`

`=>x=0`

Answer 2

a) \(x-\dfrac{2}{5}=0,24\)

\(x=0,24+\dfrac{2}{5}\)

\(x=0,64\)

b) \(2^{x+3}\cdot4^2=128\)

\(2^{x+3}\cdot16=128\)

\(2^{x+3}=\dfrac{128}{16}\)

\(2^{x+3}=8\)

\(\Rightarrow8=2^3\Rightarrow2^{0+3}\)

\(\Rightarrow x=0\)