Question

Answer 1

\(a,16x^2=9\\ x^2=\dfrac{9}{16}\\ =>\left[{}\begin{matrix}x=\dfrac{3}{4}\\x=-\dfrac{3}{4}\end{matrix}\right.\\ b,2\left(x+1\right)=3\\ 2x+2-3=0\\ 2x-1=0\\ x=\dfrac{1}{2}\\ c,\left(x-2\right)=\dfrac{3}{4}:\dfrac{1}{3}\\ x-2=\dfrac{9}{4}\\ x=\dfrac{9}{4}+2\\ x=\dfrac{17}{4}\\ d,\sqrt{x}=\dfrac{2}{3}\\ đkx\ge0\\ \left(\sqrt{x}\right)^2=\dfrac{4}{9}\\ x=\dfrac{4}{9}\left(thoaman\right)\)