\(A=\dfrac{\dfrac{sin^2a}{sin^2a}+\dfrac{1}{sin^2a}}{\dfrac{2sina.cosa}{sin^2a}}=\dfrac{1+\left(1+cot^2a\right)}{2cota}=\dfrac{2+\left(\dfrac{1}{2}\right)^2}{2.\dfrac{1}{2}}=\dfrac{9}{4}\)
\(B=\dfrac{\dfrac{3sina}{cosa}+\dfrac{cosa}{cosa}}{\dfrac{sina}{cosa}-\dfrac{cosa}{cosa}}=\dfrac{3tana+1}{tana-1}=\dfrac{3.2+1}{2-1}=7\)


