a) \(m_{H_2SO_4}=9,8\%.200=19,6\left(g\right)\Rightarrow n_{H_2SO_4}=\dfrac{19,6}{98}=0,2\left(mol\right)\)
PTHH: Al2O3 + 3H2SO4 ---> Al2(SO4)3 + 3H2
\(\dfrac{1}{15}\)<----0,2----------->\(\dfrac{1}{15}\)
=> \(m=\dfrac{1}{15}.102=6,8\left(g\right)\)
c) \(a=\dfrac{1}{15}.342=22,8\left(g\right)\)
