Question

Answer 1

`(-5/4x + 3,25).[ 3/5 - (-5/2 x)] = 0`

`(-5/4 x + 3,25) .(3/5 + 5/2 x )=0`

`@TH1:`

`-5/4 x + 3,25=0`

`-5/4x = 0 - 3,25`

`-5/4x = -3,25`

`x=-3,25 : (-5/4)`

`x=3,25 : 5/4`

`x=13/5`

`@TH2:`

`3/5 + 5/2 x = 0`

`5/2 x = 0 -3/5`

`5/2 x = -3/5`

`x=-3/5 : 5/2`

`x=-6/25`

Vậy `x = {13/5 ; -6/25}`