Question

Answer 1

a) 

$Mg + 2HCl \to MgCl_2 + H_2$
$MgO +2HCl \to MgCl_2 + H_2O$

b) Gọi $n_{Mg} = a(mol) ; n_{MgO} = b(mol) \Rightarrow 24a + 40b = 9,2(1)$

Theo PTHH : $n_{H_2} = n_{Mg} = a = \dfrac{1,12}{22,4} = 0,05(2)$

Từ (1)(2) suy ra a = 0,05 ; b = 0,2

$m_{Mg} = 0,05.24 = 1,2(gam)$
$m_{MgO} = 0,2.40 = 8(gam)$
c)

Theo PTHH, $n_{HCl} = 2n_{Mg} + 2n_{MgO} = 0,5(mol)$
$m_{dd\ HCl} = \dfrac{0,5.36,5}{14,6\%} = 125(gam)$