Question

Answer 1

\(4,-\dfrac{4}{5}-x=\dfrac{3}{8}-\dfrac{-1}{2}\\ -\dfrac{4}{5}-x=\dfrac{3}{8}+\dfrac{4}{8}\\ -\dfrac{4}{5}-x=\dfrac{7}{8}\\ x=-\dfrac{4}{5}-\dfrac{7}{8}\\ x=-\dfrac{32}{40}-\dfrac{35}{40}\\ x=-\dfrac{67}{40}\)

\(5,\left(x+\dfrac{3}{4}\right)-\dfrac{1}{3}=\dfrac{2}{3}+\dfrac{11}{-12}\\ \left(x+\dfrac{3}{4}\right)-\dfrac{1}{3}=\dfrac{8}{12}-\dfrac{11}{12}\\ \left(x+\dfrac{3}{4}\right)-\dfrac{1}{3}=-\dfrac{1}{4}\\ x+\dfrac{3}{4}=-\dfrac{1}{4}+\dfrac{1}{3}\\ x+\dfrac{3}{4}=\dfrac{1}{12}\\ x=\dfrac{1}{12}-\dfrac{3}{4}\\ x=-\dfrac{2}{3}\)