Question

Answer 1

\(\dfrac{9}{8}.\dfrac{3x-6}{-7}+\dfrac{1}{2}=\dfrac{8}{16}\)

\(\Rightarrow\dfrac{9}{8}.\dfrac{3x-6}{-7}=0\)

\(\Rightarrow\dfrac{3x-6}{-7}=0\)

\(\Rightarrow3x-6=0\Rightarrow x=2\)

Answer 2

\(\dfrac{9}{8}\cdot\dfrac{3x-6}{-7}+\dfrac{1}{2}=\dfrac{8}{16}\\ \Leftrightarrow\dfrac{9}{8}\cdot\dfrac{3x-6}{-7}=\dfrac{8}{16}-\dfrac{1}{2}=0\\ \Leftrightarrow\dfrac{3x-6}{-7}=0\\ \Leftrightarrow3x-6=0\\ \Leftrightarrow x=2\)