\(1,=2^3.2^2=2^{3+2}=3^5\\ 2,=2^3.2^3=2^{3+3}=2^6\\ 3,=3^7.3^2=3^{7+2}=3^9\)
\(4,=3^5.2^5.2^2=\left(3.2\right)^5.2^2=6^5.4\) (vậy đc tính ko)
\(5,=4^3.4^2=4^{3+2}=4^5\\ 6,=4^6.4^2=4^{6+2}=4^8\\ 7,=4^6.4^3=4^{6+3}=4^9\\ 8,=5^4.5^2=5^{4+2}=5^6\\ 9,=6^3.6^2=6^{3+2}=6^5\\ 10,=6^8.6^3=6^{8+3}=6^{11}\)
