`(x-1/3)^3 = 8/27`
`(x-1/3)^3 = (2/3)^3`
`x-1/3=2/3`
`x=2/3+1/3`
`x=3/3`
`x=1`
Vậy `x=1`
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`(x-1/8)^3=(-8/125)`
`(x-1/8)^3=(-2/5)^3`
`x-1/8=-2/5`
`x=-2/5+1/8`
`x=-16/40 + 5/40`
`x=-11/40`
Vậy `x=-11/40`
`a, (x-1/3)^3 = 8/27`
`=> x - 1/3 = 2/3`
`=> x = 1/3 + 2/3`
`=> x = 1`.
`b, (x-1/8)^3 = -8/125`
`=> x - 1/8 = -2/5`
`=> x = -2/5 + 1/8`
`=> x= -11/40`
